Final answer:
The velocity of an electron in the first orbit of a Li2+ ion is four times higher than its velocity in the second orbit of a hydrogen atom.
Step-by-step explanation:
The velocity of an electron in the first orbit of a Li2+ ion can be calculated using the Bohr model of the atom. According to the Bohr model, the electron's velocity in a specific orbit is inversely proportional to the radius of the orbit. Since the second orbit of a hydrogen atom is four times larger than the first orbit, the electron's velocity in the first orbit of a Li2+ ion would be four times higher than its velocity in the second orbit of a hydrogen atom.
Let's assume that the velocity of the electron in the second orbit of a hydrogen atom is represented by 'x'.
Therefore, the velocity of the electron in the first orbit of a Li2+ ion would be equal to 4x.