Question

A card game has the following rules:pick one card from anywhere in shuffled deck. a number card wins its number value in dollars. A face card wins $20.an ace wins $100

Answer 1

A card game has the following rules:pick one card from anywhere in shuffled deck. a number card wins its number value in dollars. A face card wins $20.an ace wins $100.

The card game described in the search results is called "Ace Race". However, there are several other card games and dice games that use the term "Ace" in their name, such as "Aces Up".

Step-by-step explanation:

The card game described in the search results is called "Ace Race". However, there are several other card games and dice games that use the term "Ace" in their name, such as "Aces Up", Aces, and a game played in South Asia called "Ace". These games have different rules and objectives, and some of them involve winning money or buying drinks for other players.

Answer 2

In this case, the net expected value in this card game is approximately $16.46.

Step-by-step explanation:

To calculate the net expected value in the given card game, we need to consider the probabilities of drawing each type of card and their corresponding values.

Let's break it down step by step:

1. Probability of drawing a number card: In a standard deck of 52 cards, there are 36 number cards (2-10) since face cards (Jack, Queen, and King) and Aces are not considered number cards. Therefore, the probability of drawing a number card is 36/52 or 9/13.

2. Probability of drawing a face card: There are 12 face cards (Jack, Queen, and King) in a standard deck. So, the probability of drawing a face card is 12/52 or 3/13.

3. Probability of drawing an Ace: There are 4 Aces in a standard deck. Hence, the probability of drawing an Ace is 4/52 or 1/13.

Now, let's calculate the expected value for each type of card:

- Expected value of a number card: Since a number card wins its number value in dollars, the expected value for a number card is the average of the possible values, which is (2 + 3 + 4 + ... + 10) divided by the total number of number cards (36). This gives us an expected value of (2+3+4+...+10)/36 = 6.

- Expected value of a face card: As stated in the rules, a face card wins $20. So, the expected value for a face card is $20.

- Expected value of an Ace: According to the rules, an Ace wins $100. Hence, the expected value for an Ace is $100.

To calculate the net expected value, we multiply the expected value of each type of card by its respective probability and sum them up:

Net Expected Value = (Probability of drawing a number card * Expected value of a number card) + (Probability of drawing a face card * Expected value of a face card) + (Probability of drawing an Ace * Expected value of an Ace)

Substituting the values:

• Net Expected Value = (9/13 * $6) + (3/13 * $20) + (1/13 * $100)
• Net Expected Value = $54/13 + $60/13 + $100/13
• Net Expected Value = ($54 + $60 + $100)/13
• Net Expected Value = $214/13

After simplifying, the net expected value is approximately $16.46.

Therefore, the net expected value in this card game is approximately $16.46.

Your question is incomplete, but most probably the full question was:

A card game has the following rules: Pick one card from anywhere in shuffled deck. a number card wins its number value in dollars. A face card wins $20.an ace wins $100. Calculate The net expected value .