Question

A water balloon was thrown from a window. The height of the water

balloon over time can be modeled by the function y=-16x² +160x+50.
What was the height of the water balloon after it was thrown?
A) 8 poi
B) 350 ft
C) 400 ft
D) 450 ft
E) 500 ft
F) 550 ft
G) 600 ft

Answer 1

The initial height of the water balloon when it was thrown was 50 feet, calculated by substituting x = 0 into the equation y=-16x² +160x+50.

Step-by-step explanation:

To find the height of the water balloon right after it was thrown, we need to evaluate the quadratic function y=-16x² +160x+50 at x = 0, because the time at the moment of the throw is x = 0 seconds.

Substituting x = 0 into the equation, we get:

y = -16(0)² + 160(0) + 50

y = 0 + 0 + 50

y = 50 feet

Therefore, the initial height of the water balloon when it was thrown was 50 feet. This height corresponds to the constant term in the quadratic equation, which represents the initial height from which the object was thrown or fired.