99.9k views
2 votes
Harold cut 18 one over two. inches off a rope that was 60 inches long.

User Saturnix
by
7.7k points

1 Answer

5 votes

Final answer:

Harold cut 18 one over two inches off a rope that was 60 inches long. To solve this problem, you need to subtract the length that Harold cut from the original length of the rope. By converting the mixed number to an improper fraction and finding a common denominator, you can subtract the fractions to find the length Harold cut off the rope, which is 203/4 inches.

Step-by-step explanation:

Harold cut 18 one over two inches off a rope that was 60 inches long.

To solve this problem, we need to subtract the length that Harold cut from the original length of the rope.

Original length of the rope = 60 inches

Length that Harold cut = 18 one over two inches

To subtract this length, we can convert it to a mixed number:

18 one over two inches = 18 + (1/2)

Now we can subtract this length from the original length of the rope:

60 inches - 18 one over two inches

To subtract mixed numbers, we need to convert them to improper fractions:

18 one over two = (2 * 18) + 1 = 37

Now we can subtract the lengths:

60 inches - (37/2) inches

To subtract fractions, we need a common denominator. The denominator of 2 can be multiplied by 2 to get a common denominator of 4:

60 inches - (37/2) inches = (240/4) inches - (37/2) inches

Now we can subtract the fractions by subtracting the numerators:

(240 - 37)/4 inches = 203/4 inches

So, Harold cut 203/4 inches off the rope.

User Bethina
by
8.0k points