Final answer:
To calculate the number of hydrogen and oxygen molecules in 36 g of water, we determine that there are 2 moles of water, which leads to 1.2044 x 10²´ molecules of H₂ and 1.2044 x 10²´ molecules of O.
Step-by-step explanation:
The question is about calculating the number of hydrogen and oxygen molecules in a solution of glucose and water. First, we have to consider the molar mass of water (H₂O), which is 18.02 g/mol. This means that 36 g of water is equivalent to 36 g / 18.02 g/mol = 2 moles of water. Since each molecule of water contains 2 atoms of hydrogen and 1 atom of oxygen, we have 2 moles * Avogadro's number (6.022 × 10²³) of hydrogen atoms and the same number of moles of oxygen atoms.
Therefore, in 36 g of water, there are:
- 4 moles of hydrogen atoms (because each molecule has 2 hydrogen atoms)
- 2 moles of oxygen atoms
When calculating the number of molecules, we consider 4 moles of hydrogen atoms to yield 2 moles of H₂ molecules (because each H₂ molecule contains 2 hydrogen atoms), and 2 moles of oxygen atoms yield 2 moles of O. Thus, there are:
- 2 moles * 6.022 × 10²³ = 1.2044 × 10²´ molecules of H₂
- 2 moles * 6.022 × 10²³ = 1.2044 × 10²´ molecules of O (Although oxygen usually exists as O₂ in nature, in this context, we are referring to the individual oxygen atoms present in water molecules.)