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The focal point of the quadratic y = 1200 ? – 7 is at (0, p). What is the value of p?

User UmeshR
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1 Answer

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Final answer:

The focal point of a parabola cannot be determined from the provided equation as it contains a typo. The correct form must be used and the coefficients identified to give the value of 'p' using the relation between the focal distance and the leading coefficient, a.

Step-by-step explanation:

The question provided contains a typo or mistake. The correct standard form for a quadratic equation should be y = ax² + bx + c, where a, b, and c are constants, and the quadratic represents a parabola in Cartesian coordinates. If the equation is intended to represent a parabola, it's important to correct it to fit the standard form and then identify the focal point. The focal point of a parabola y = ax² + bx + c is given by the formula (h, k + 1/(4a)) when the parabola opens up or down. For a parabola y = ax², the vertex is at the origin (0,0) and the focal distance p is 1/(4a). However, without the correct quadratic coefficients in the provided equation, it is not possible to determine the focal point. To find the focal point, the equation has to be corrected first.

User Wrygiel
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