Question

"Mr. Palmer walks around his classroom thousands of times. He accelerates from rest (Om/s) to a velocity of 1.4 m/s. It takes him 0.8 seconds to

accomplish this change in velocity. What is his acceleration?
Do not include units in your answer. Round your to 2 decimal places if possible"

Answer 1

Mr. Palmer's acceleration is found by dividing the change in velocity by the time it takes to change, resulting in an acceleration of 1.75 m/s^2.

Step-by-step explanation:

Mr. Palmer's acceleration can be calculated using the formula acceleration = (final velocity - initial velocity) / time. The initial velocity (vi) is 0 m/s, and the final velocity (vf) is 1.4 m/s. The time (t) taken is 0.8 seconds. Therefore, acceleration (a) can be calculated as:

a = (vf - vi) / t

a = (1.4 m/s - 0 m/s) / 0.8 s

a = 1.75 m/s2

Thus, Mr. Palmer's acceleration is 1.75 m/s2.