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What is the equation of a line that passes through the points (3, 6) and (8, 4)?

O y= 5/2 x -3/2
O y= 5/2 x 27/2
O y= -2/5 x 24/5
O y= -2/5x + 36/5

1 Answer

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Final answer:

The equation of a line passing through the points (3, 6) and (8, 4) is calculated by first determining the slope, which is -2/5, and then using one of the points to find the y-intercept, resulting in y = -2/5x + 36/5.

Step-by-step explanation:

To find the equation of a line that passes through the points (3, 6) and (8, 4), we first need to calculate the slope (m) of the line using the formula m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points. Plugging in our points, we get m = (4 - 6) / (8 - 3) = -2 / 5.

Next, we use the slope-intercept form of a line, which is y = mx + b, to find the y-intercept (b). We can use one of the points to solve for b. Let's use (3, 6):

6 = (-2/5)(3) + b

6 = -6/5 + b

6 + 6/5 = b

30/5 + 6/5 = b

36/5 = b

Now we have both the slope and the y-intercept, so the equation of the line is y = -2/5x + 36/5.

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