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"The initial speed of a body is 4.32 m/s.

What is its speed after 2.86 s if it accelerates
uniformly at 3.22 m/s²?"

1 Answer

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Final answer:

The final speed of the body after 2.86 seconds, given its initial speed of 4.32 m/s and an acceleration of 3.22 m/s², is calculated using the kinematic equation v = u + at. After performing the calculation, the final speed is found to be 13.53 m/s.

Step-by-step explanation:

The question asks about the final speed of a body given its initial speed, time elapsed, and uniform acceleration. To calculate the final speed of the body (v), we use the kinematic equation v = u + at, where u is the initial velocity, a is the acceleration, and t is the time.

In this scenario:

  • Initial velocity (u) = 4.32 m/s
  • Acceleration (a) = 3.22 m/s2
  • Time (t) = 2.86 s

Substituting these values into the equation:

v = 4.32 m/s + (3.22 m/s2 × 2.86 s)

After calculations,

v = 4.32 m/s + 9.21 m/s = 13.53 m/s

So, the final speed of the body after 2.86 seconds is 13.53 m/s.

User Yannick Smits
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