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The Smith family went to the theater to see a movie. Adult ticket cost $12 and child tickets cost $9. If they spent $75 total and purchased 7 tickets. How many of each were purchased?

1 Answer

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Final answer:

The Smith family bought 4 adult tickets and 3 child tickets to the theater by using a system of equations to solve for the quantity of each ticket type based on the total cost and the number of tickets purchased.

Step-by-step explanation:

To solve this problem, we can use a system of equations. Let 'a' represent the number of adult tickets and 'c' represent the number of child tickets. We are given that adult tickets cost $12 and child tickets cost $9. Also, the family bought 7 tickets in total and spent $75.

The following are our two equations based on the information provided:

  • Equation for the total cost: 12a + 9c = 75
  • Equation for the total number of tickets: a + c = 7

To solve these equations, we can first solve the second equation for one of the variables and then substitute it into the first equation.

Solve the second equation for 'a':

a = 7 - c

Now, substitute 'a = 7 - c' into the first equation:

12(7 - c) + 9c = 75

84 - 12c + 9c = 75

Merge like terms:

-3c = -9

Divide by -3 to find 'c':

c = 3

Now that we have the number of child tickets, we can find the number of adult tickets by substituting 'c' back into one of the equations. We'll use the equation a + c = 7:

a + 3 = 7

Subtract 3 from both sides to find 'a':

a = 4

So the Smith family bought 4 adult tickets and 3 child tickets.

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