99.9k views
3 votes
A student’s percent error for the density of gold was 14% under the accepted value of 19.3 g ml-1. What was the student’s experimental value?

User Kylejs
by
7.5k points

1 Answer

2 votes

Final answer:

The student's experimental value for the density of gold is 21.002 g/ml.

Step-by-step explanation:

The student's percent error can be calculated using the formula:

Percent Error = (Experimental Value - Accepted Value) / Accepted Value * 100%

Given that the percent error is 14% and the accepted value is 19.3 g/ml, we can rearrange the formula to solve for the experimental value:

Experimental Value = Accepted Value + Percent Error * Accepted Value / 100%

Substituting the values into the formula:

Experimental Value = 19.3 g/ml + 14% * 19.3 g/ml / 100%

Simplifying the equation:

Experimental Value = 19.3 g/ml + 2.702 g/ml

Experimental Value = 21.002 g/ml

User Jzacharuk
by
7.5k points