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An object is dropped from a height of 58.3 meters. Determine how long it takes the

object to hit the ground. Ignore air resistance.

1 Answer

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Final answer:

To find out how long it takes an object to fall from a height of 58.3 meters without air resistance, we can use the formula h = ½gt² and solve for t, which results in approximately 3.45 seconds for the object to reach the ground.

Step-by-step explanation:

Calculating Time for an Object to Hit the Ground

To determine how long it takes an object to hit the ground when dropped from a height of 58.3 meters, ignoring air resistance, we can use the physics equation for the free fall motion under the influence of gravity. The formula is h = ½gt², where h is the height from which the object is dropped, g is the acceleration due to gravity (approximately 9.8 m/s² on Earth), and t is the time in seconds.

By rearranging the formula to solve for t, we get ² = 2h/g, and then take the square root of both sides to find t. Inserting the given height of 58.3 meters and assuming g = 9.8 m/s², the calculation for t is as follows:

t = sqrt(2*58.3/9.8) ≈ sqrt(11.9) ≈ 3.45 seconds (approximately)

Therefore, it takes roughly 3.45 seconds for the object to hit the ground.

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