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Adam runs at 6.0 m/s for 10.0 s and Jason accelerates from 4.0 m/s to 10.0 m/s in 10.0s. How much farther does Jason travel than Adam

1 Answer

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Final answer:

Jason travels 10.0 m farther than Adam.

Step-by-step explanation:

To find how much farther Jason travels than Adam, we need to calculate the distance each of them covers. Adam runs at a constant speed of 6.0 m/s for 10.0 s, so his distance is given by:

Distance = Speed × Time

Distance = 6.0 m/s × 10.0 s = 60.0 m

Jason accelerates from 4.0 m/s to 10.0 m/s in 10.0 s. We can find his average speed using the formula:

Average Speed = (Initial Speed + Final Speed) / 2

Average Speed = (4.0 m/s + 10.0 m/s) / 2 = 7.0 m/s

Then, we calculate his distance using his average speed and the time:

Distance = Average Speed × Time

Distance = 7.0 m/s × 10.0 s = 70.0 m

Therefore, Jason travels 70.0 m - 60.0 m = 10.0 m farther than Adam.

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