Final answer:
The equation of the line with a slope of -2/3 that passes through the point (-3, -1) is y = (-2/3)x - 3.
Step-by-step explanation:
The equation of the line with a slope of -2/3 that passes through the point (-3, -1) can be found using the point-slope form of a linear equation, which is y - y1 = m(x - x1). Here, m is the slope and (x1, y1) is the point through which the line passes. Substituting the given values, we get y - (-1) = (-2/3)(x - (-3)), which simplifies to y + 1 = (-2/3)(x + 3). To write it in slope-intercept form, distribute the slope across the parentheses to get y + 1 = (-2/3)x - 2, and then subtract 1 from both sides to isolate y, resulting in the final equation y = (-2/3)x - 3.