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Which equation results from isolating a radical term and squaring both sides of the equation for the equation √x+6+ √x=8?

a. X+6 = 64 - x
b. X+6 - 64+x
c. X+6 = 64+x-16 /
d. x+6 = 64+x+16V

User Shaharg
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Final answer:

To solve the given equation by isolating one radical and squaring both sides, it requires isolating \( \sqrt{x} \), squaring both sides, and then further manipulation to ultimately remove the radical.

Step-by-step explanation:

The equation \( \sqrt{x+6} + \sqrt{x} = 8 \) can be solved by isolating one of the radical terms and then squaring both sides of the equation. Isolating \( \sqrt{x} \) and squaring would give us:

\( (\sqrt{x+6} - \sqrt{x})^2 = (8 - \sqrt{x})^2 \)

Expanding both sides and simplifying would result in:

\( x+6 - 2\sqrt{x+6}\sqrt{x} + x = 64 - 16\sqrt{x} + x \).

As the equation contains a radical term \( \sqrt{x} \), further manipulation is needed to isolate and square the term again to remove the radical. This process can be extensive and requires careful simplification and the use of algebraic identities.

User Yuriy Barvinchenko
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