Question

A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the cabinet is used to store bottles of pentane, ethanolamine, diethylamine, glycerol, and carbon tetrachloride. The chemist plans to try to identify the unknown liquid by measuring the density and comparing to known densities. First, from his collection of Material Safety Data Sheets (MSDS), the chemist finds the following information: liquid density pentane 0.63gmL, ethanolamine 1.0gmL, diethylamine 0.71gmL, glycerol 1.3gmL, carbon tetrachloride 1.6gmL Next, the chemist measures the volume of the unknown liquid as 1737.cm3 and the mass of the unknown liquid as 1.23kg . Calculate the density of the liquid. Be sure your answer has the correct number of significant digits.

Answer 1

0.71 g/mL

The liquid is diethylamine

Step-by-step explanation:

Mass of the liquid = 1.23 kg of 1.23 * 10^3 g

Volume of the liquid = 1737.cm3

Let us remember that density is obtained as;

Density= mass/volume

Density= 1.23 * 10^3 g/1737cm^3

Density= 0.71 g/cm^3

Since we know that 1 mL=1 cm3 . So, 1 g/mL=1 g/cm3

So we can also write;

Density= 0.71 g/mL

The liquid is diethylamine