103k views
2 votes
Suppose h(x) =√3-2x^2. Find two functions f and g such that (f°g) (x) = h(x)

1 Answer

4 votes

Final answer:

To find two functions f and g such that (f°g) (x) = h(x), we need to understand the composition of functions. Let's first rewrite h(x) = √3-2x² in a way that we can identify functions f and g. Now, we can see that g(x) = 3 - 2x² and f(x) = √x. (f°g) (x) = √(3 - 2x²) = h(x).

Step-by-step explanation:

To find two functions f and g such that (f°g) (x) = h(x), we need to understand the composition of functions.

The composition of two functions f and g is denoted as (f°g) (x) and it means that the output of the function g is used as the input for the function f. In this case, we need to find functions f and g such that (f°g) (x) = h(x).

Let's first rewrite h(x) = √3-2x² in a way that we can identify functions f and g. We can rewrite it as h(x) = √(3 - 2x²) = f(g(x)).

Now, we can see that g(x) = 3 - 2x² and f(x) = √x.

Therefore, (f°g) (x) = √(3 - 2x²) = h(x).

User Melchiar
by
7.4k points