Question

Find the three consecutive odd integers with a sum of 27.

Answer 1

The three consecutive odd integers with a sum of 27 are 7, 9, and 11.

Step-by-step explanation:

Let's denote the first odd integer as x. Since the three integers are consecutive odd integers, the next two integers are x + 2 and x + 4. We are given that the sum of the three integers is 27, so we can set up the following equation:

x + (x + 2) + (x + 4) = 27

Combining like terms, we get:

3x + 6 = 27

Subtracting 6 from both sides, we get:

3x = 21

Dividing both sides by 3, we get:

x = 7

Now that we know x = 7, we can find the other two consecutive odd integers:

x + 2 = 7 + 2 = 9

x + 4 = 7 + 4 = 11

Therefore, the three consecutive odd integers with a sum of 27 are 7, 9, and 11.