Question

A uniform 165 N bar is supported horizontally by two identical wires A and B (Figure 1). A small 185 N cube of lead is placed three-fourths of the way from A to B . The wires are each 75.0 cm long and have a mass of 5.50 g . If both of them are simultaneously plucked at the center, what is the frequency of the beats that they will produce when vibrating in their fundamental?

Answer 1

To calculate the frequency of beats produced by two identical wires, we can use the formula for beats and the formula for the fundamental frequency of a wire.

Step-by-step explanation:

The frequency of beats produced when two identical wires are simultaneously plucked at the center can be calculated using the formula:

beats = (frequency2 - frequency1)/2

Since the wires are identical, their fundamental frequencies will be the same. The fundamental frequency of a wire can be calculated using the formula:

frequency = 1 / (2L) * sqrt(Tension / mu)

where L is the length of the wire, Tension is the tension in the wire, and mu is the linear mass density of the wire.

Using the given information, we can calculate the frequency of beats produced when the wires vibrate in their fundamental frequency.