Question

Find molarity in 1.0 grams of potassium fluoride is dissolved to make 0.10 L of solution.

Answer 1

We are given –

• Weight of
  `\bf KF` is = 1g
• Volume, V = 0.10 L

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• Molar Mass of
  `\bf KF` –

`\qquad`
`\twoheadrightarrow\bf 39.09 +18.99`

`\qquad`
`\twoheadrightarrow\bf 58.08`

Using formula –

`\qquad`
`\purple{\twoheadrightarrow\bf Molarity _((Solution)) = ( W)/(MV)}`

`\qquad`
`\twoheadrightarrow\bf Molarity _((Solution)) = ( 1)/(58.08* 0.10)`

`\qquad`
`\twoheadrightarrow\bf Molarity _((Solution)) = (1)/(5.808)`

`\qquad`
`\purple{\twoheadrightarrow\bf Molarity _((Solution)) = 0.1722M}`

• Henceforth, Molarity of the solution is = 0.1722M.

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