Question

Suppose there is a 3Mbps uplink and 10Mbps downlink between a geostationary satellite and the base station on earth. If the propagation speed is the speed of light (3 * 10^8 m/sec), the packet size is 20Mb, and the distance from the satellite to earth is 36,000 km, what is the uplink propagation delay of the link in milliseconds

Answer 1

`120\ \text{ms}`

Step-by-step explanation:

Distance between the satellite and Earth =
`36000\ \text{km}`

Speed of light =
`3* 10^8\ \text{m/s}`

Propagation delay is given by distance by the speed of light

`(36000* 10^3)/(3* 10^8)`

`=0.12\ \text{s}* 10^3`

`=120\ \text{ms}`

The uplink propagation delay of the link is
`120\ \text{ms}`.