Question

What is the pOH of a 6.5x10-3 M KOH solution

Answer 1

`\huge{ \boxed{2.19}}`

Step-by-step explanation:

The pOH of the solution can be found by using the formula:

`\bold{pOH = -log([{OH}^(-)])}`

KOH dissociates completely to produce OH ions according to the reaction equation:

`KOH \longrightarrow K^(+) + {OH}{-}`

From the reaction equation it can be concluded that the concentration of OH ions in KOH is
`6.5 * 10^(-3) M`.

`\therefore pOH= -log(6.5 * 10^(-3) \\ = 2.19`