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User Sona
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The proportion formulae for the cases of similar triangles: Case 13:
(x)/(20) = (20)/(12) (Solution: x = 6), Case 14:
(x)/(4) = (9)/(x) (Solution: x = 6), Case 15:
(x)/(3) = (5)/(x) (Solution: x = √15)

How to determine the proportion formula for each pair of similar triangles

In this question we must derive the proportion formula for each pair of two similar triangles. Two triangles are similar if both triangles have congruent angles and proportional sides. Now we proceed to construct the proportion formula for each case:

Case 13:


(x)/(20) = (20)/(12)

Whose solution is shown below:

x = 33.333

Case 14:


(x)/(4) = (9)/(x)

Whose solution is shown below:

x² = 36

x = 6

Case 15:


(x)/(3) = (5)/(x)

Whose solution is shown below:

x² = 15

x = √15

User Kendavidson
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