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A ball rolls off a table and falls 0.75m to the floor, landing with a speed of 4 m/s. What is the acceleration of the ball just before it strikes the ground?

User Jahdiel
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Final answer:

The acceleration of the ball just before it strikes the ground is approximately 11.59 m/s^2.

Step-by-step explanation:

To calculate the acceleration of the ball just before it strikes the ground, we can use the formula:

acceleration = (final velocity - initial velocity) / time

In this case, the final velocity is 4 m/s, the initial velocity is 0 m/s (since the ball starts from rest), and the time of fall is not given. However, we can use the equation for free fall:

distance = (1/2) * acceleration * time^2

Since the ball falls 0.75m, we can substitute the values to solve for time:

(1/2) * acceleration * time^2 = 0.75m

Applying the quadratic formula, we find that the time of fall is approximately 0.345s. Plugging this value into the first equation gives us:

acceleration = (4m/s - 0m/s) / 0.345s ≈ 11.59 m/s^2.

User SammyBlackBaron
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