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Find the operation f(g(x)).Given f(x) = x + 1 and g(x) = 8x – 6

A) f(g(x)) = 8x - 5
B) f(g(x)) = 2/2 + 1
C) f(g(x)) = 8√x - 4
D) f(g(x)) = 8x + 2 - 6

User Brianb
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1 Answer

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Final answer:

To find f(g(x)), substitute g(x) into f(x), yielding f(g(x)) = (8x – 6) + 1 which simplifies to f(g(x)) = 8x – 5.

Step-by-step explanation:

To find the operation f(g(x)), we first need to substitute the function g(x) into the function f(x). Given f(x) = x + 1 and g(x) = 8x – 6, we start by replacing every occurrence of x in f(x) with g(x).

Step 1: Substitute g(x) into f(x):
f(g(x)) = f(8x – 6)

Step 2: Apply the function f(x) to g(x):
f(g(x)) = (8x – 6) + 1

Step 3: Simplify the expression:
f(g(x)) = 8x – 6 + 1f(g(x)) = 8x – 5

The correct operation of f(g(x)) is 8x - 5.

User StackPusher
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