Final answer:
The direction of the vector with components Bx=-1.33m and by=2.81m is approximately 65 degrees north of east. This is found by calculating the arctan of the y-component divided by the x-component and adjusting for the vector being in the second quadrant.
Step-by-step explanation:
To find the direction of the vector with components Bx=-1.33m and by=2.81m, we can calculate the angle θ it makes with the positive x-axis using the tangent function:
tan(θ) = By / Bx
θ = arctan(By / Bx)
Plug in the given values:
θ = arctan(2.81 / (-1.33))
θ is calculated to be approximately 115 degrees.
However, since Bx is negative and By is positive, the vector lies in the second quadrant.
The angle typically should be measured from the positive x-axis, so you would subtract this angle from 180 degrees to find the direction north of east:
Direction = 180 degrees - θ
Therefore, the direction of the vector is approximately 65 degrees north of east.