Question

The concentration (m) of HCl in a solution prepared by dissolving 5.5 g of HCl in 200 g of C2H6O is ________ m. The density of the solution is 0.79 g/ml.

a) 0.44 M
b) 1.04 M
c) 2.31 M
d) 0.85 M

Answer 1

To calculate the molarity of an HCl solution made by dissolving 5.5 g HCl in 200 g of ethanol, convert the mass of HCl to moles and the mass of ethanol to liters using its density. The calculated molarity is 0.595 M, but this result does not match the provided options, suggesting a potential error in the question or the options provided.

Step-by-step explanation:

The concentration (m) of HCl in a solution prepared by dissolving 5.5 g of HCl in 200 g of C2H6O (ethanol) can be determined using the formula for molarity, which is the number of moles of solute per liter of solution (M = moles/L). First, calculate the number of moles of HCl:

Molar mass of HCl = 36.5 g/mol.

5.5 g HCl x (1 mol HCl / 36.5 g HCl) = 0.15068 mol HCl

Since the density of the solution is 0.79 g/ml, we can find the volume of the solution:

200 g of C2H6O / (0.79 g/ml) = 253.16 ml = 0.25316 L

Now, calculate the molarity:

0.15068 mol HCl / 0.25316 L = 0.595 M

However, the answer is not in the provided options, indicating that there might be a typo in the question or the options given. It is also possible that the question intended for the solution to be made up to a specific volume with C2H6O which is not indicated. In practice, when HCl is dissolved in ethanol, the molarity can change as it is not an aqueous solution. Therefore, check the question and the provided options again.