Question

What is the other dimension of the rectangle with an area of 8x^6y^7 - 6x^5y^5 units, given that one dimension is 2x^3y^4 units?

A) 4x^3y^3
B) -4x^3y^3
C) 4x^3y
D) -4x^3y

Answer 1

The other dimension of the rectangle is 4x^3y^3 - 3y.

Step-by-step explanation:

To find the other dimension of the rectangle, we can use the formula for the area of a rectangle which is length times width. Given that one dimension is 2x^3y^4, we can substitute this into the formula:

Area = 8x^6y^7 - 6x^5y^5

8x^6y^7 - 6x^5y^5 = 2x^3y^4 * width

Divide both sides by 2x^3y^4 to solve for the width:

width = (8x^6y^7 - 6x^5y^5) / (2x^3y^4)

Simplifying the expression:

width = 4x^3y^3 - 3y

Therefore, the other dimension of the rectangle is 4x^3y^3 - 3y.