Question

How many solutions does each polynomial have?

Equation: y = -6x^2 + 2x - 7
Number of Solutions:
a) None
b) One
c) Two
d) More than two

Answer 1

The given quadratic polynomial has no real solutions.

Step-by-step explanation:

The given equation is a quadratic function with the form ax^2 + bx + c = 0. In this case, a = -6, b = 2, and c = -7. To determine the number of solutions, we can use the discriminant (D) of the quadratic formula. The discriminant is given by D = b^2 - 4ac.

If the discriminant is positive (D > 0), there are two distinct real solutions. If the discriminant is zero (D = 0), there is one real solution. If the discriminant is negative (D < 0), there are no real solutions.

In this case, the discriminant is D = 2^2 - 4(-6)(-7) = 4 - 168 = -164, which is negative. Therefore, the polynomial has no real solutions. The answer is (a) None.