Final answer:
To calculate the final velocity after a 3.12 s interval with a constant force applied, use Newton's second law to find acceleration and then the formula v = u + at to find velocity, taking into account any initial velocity.
Step-by-step explanation:
To determine the velocity at the end of a 3.12 s interval when a constant force is applied, one needs to apply the principles of Newton's second law of motion, which states that force equals mass times acceleration (F = ma). Given that a constant force of 4.27 N is applied on an object, and assuming the mass of the object is known, the acceleration can be calculated by re-arranging the formula to a = F/m. Once the acceleration is found, the final velocity can be calculated using the equation v = u + at, where u is the initial velocity, a is the acceleration, and t is the time interval.
For example, if the object's mass was 2 kilograms and started from rest, the calculation would be as follows:
- First, calculate the acceleration: a = F/m = 4.27 N / 2 kg = 2.135 m/s2
- Then calculate the final velocity: v = 0 m/s + (2.135 m/s2)(3.12 s) = 6.6612 m/s
It's important to note that the initial velocity is factored into the computation if the object was already in motion.