Question

An artist shot a 0.06 KG arrow at a target. The air accelerated it at 5000 M/S^2 to reach a speed of 50.0 M/SS. During this acceleration, what was the net force on the arrow to the nearest Newton?

a) 0.3 N
b) 1.5 N
c) 3 N
d) 15 N

Answer 1

The net force on the arrow is 300 N.

Step-by-step explanation:

The net force on an object can be calculated using Newton's second law of motion: force = mass x acceleration. In this case, the mass of the arrow is 0.06 kg and the acceleration is 5000 m/s^2. So the net force on the arrow can be calculated as:

Force = 0.06 kg x 5000 m/s^2 = 300 N.

Therefore, the net force on the arrow is 300 N to the nearest Newton. The correct answer is (c) 3 N.