Question

Calculate the specific heat capacity of iron when a 17.55-g piece of iron absorbs 1066.88 joules of heat energy and its temperature changes from 55 °C to 195 °C. Please provide the specific heat capacity value.

Answer 1

The specific heat capacity of iron for a 17.55-g piece absorbing 1066.88 joules and undergoing a temperature change from 55 °C to 195 °C is 0.434 J/g°C.

Step-by-step explanation:

To calculate the specific heat capacity of iron when a 17.55-g piece of iron absorbs 1066.88 joules of heat energy and its temperature changes from 55 °C to 195 °C, you can use the formula q = mcΔT, where q is the heat absorbed, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Here, we know that q = 1066.88 J, m = 17.55 g, and ΔT is the change in temperature from 55 °C to 195 °C, which equals 140 °C.

The specific heat capacity (c) can be found by rearranging the formula to c = q / (mΔT). Plugging in the values gives us:

c = 1066.88 J / (17.55 g × 140 °C)

c = 1066.88 J / (2457 g°C)

The calculated specific heat capacity is c = 0.434 J/g°C.