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2^x * 4^(x+1) = 8^2 - 3. Solve to find the value of x.

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Final answer:

To solve the equation 2^x * 4^(x+1) = 8^2 - 3 to find the value of x, simplify the equation by rewriting each power of 2, 4, and 8 in terms of a common base. Equate the simplified exponents and solve for x.

Step-by-step explanation:

To solve the equation 2^x * 4^(x+1) = 8^2 - 3 for x, we can simplify the equation by expressing each power of 2, 4, and 8 in terms of a common base. Since 4 is equal to 2^2, and 8 is equal to 2^3, we can rewrite the equation as:

2^x * (2^2)^(x+1) = (2^3)^2 - 3

Using the properties of exponents, we can simplify the equation as follows:

2^x * 2^(2(x+1)) = 2^(3*2) - 3

Now that the bases are the same, we can equate the exponents:

x + 2(x+1) = 3*2 - 3

Simplifying the equation further:

x + 2x + 2 = 6 - 3

Combining like terms:

3x + 2 = 3

Subtracting 2 from both sides:

3x = 1

Dividing both sides by 3:

x = 1/3

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