Question

A hockey player applied a 20N force to accelerate a 0.25kg hockey puck at 20m/s on a rough horizontal surface (mushy ice or during the last period of the game).

A) Draw a free-body diagram for the puck.
B) Find the force of friction slowing the puck down.
C) Find the normal force acting on the puck.

Answer 1

B) The force of friction is 1.23 N

C) The normal force acting on the puck is 2.45 N.

How to find friction and normal force?

B) To find the force of friction (Ff), use the following equation:

Ff = μ × Fn

where:

μ = coefficient of friction between the puck and the ice. Since the ice is mushy or it's the last period of the game, assume μ = 0.5.

Fn = normal force acting on the puck.

Find the normal force (Fn) using the following equation:

Fn = mg

where:

m = mass of the puck (0.25 kg)

g = acceleration due to gravity (9.8 m/s²)

Plugging in the values:

Fn = (0.25 kg) × (9.8 m/s²)

= 2.45 N

Therefore, the force of friction is:

Ff = (0.5) × (2.45 N)

= 1.23 N

C) The normal force acting on the puck is 2.45 N.