Final answer:
To solve this problem, set up a system of equations with x and y representing the number of student and adult tickets sold. None of the options provided are correct.
Step-by-step explanation:
To solve this problem, we can set up a system of equations. Let x be the number of student tickets sold and y be the number of adult tickets sold.
We know that the cost of a student ticket is $5 and the cost of an adult ticket is $7.
From the given information, we can write the following equations:
x + y = 290 (equation 1)
5x + 7y = 1790 (equation 2)
We can solve this system of equations to find the values of x and y:
Multiplying equation 1 by 5, we get:
5x + 5y = 1450 (equation 3)
Subtracting equation 3 from equation 2, we get:
5y - 5y = 1790 - 1450
0 = 340
This is not possible, so there is no solution that satisfies both equations. Therefore, none of the given options (a, b, c, or d) is correct.