Question

What is the pressure, in atm, in a 2.00 l tank with 6.65 moles of fluorine at 49.4 °c?

a) 0.392 atm
b) 1.57 atm
c) 3.14 atm
d) 6.28 atm

Answer 1

By using the ideal gas equation, we can determine the pressure in an 2.00 L tank with 6.65 moles of fluorine at 49.4 °C. The pressure is approximately 6.28 atm. Therefore correct option is A

Step-by-step explanation:

To find the pressure in atm, we can use the ideal gas law equation: PV = nRT.

P represents pressure, V represents volume, n represents the number of moles, R is the gas constant, and T is the temperature in Kelvin. In this case, we have the values for V, n, and T, so we can rearrange the equation to solve for P.

Plugging in the values: P = (nRT) / V = (6.65 mol * 0.0821 L*atm/mol*K * (49.4 + 273.15) K) / 2.00 L.

After performing the calculation, the pressure is approximately 6.28 atm.

Therefore, the correct answer is option d) 6.28 atm.