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Diane, Abdul, and Carlos have a total of $89 in their wallets. Abdul has 4 times what Carlos has. Carlos has $7 more than Diane. How much do they have in their wallets?

A. Diane: $18, Abdul: $73, Carlos: $18
B. Diane: $20, Abdul: $60, Carlos: $9
C. Diane: $15, Abdul: $60, Carlos: $14
D. Diane: $19, Abdul: $64, Carlos: $6

1 Answer

2 votes

Final answer:

Using algebra to define variables and set up an equation with the given information, it's determined that Diane has $9, Carlos has $16, and Abdul has $64. However, none of the provided answer choices match these amounts, indicating an issue with the options given.

Step-by-step explanation:

To solve the problem, let's use algebra. We'll start by defining our variables:
Diane has X dollars,
Carlos has X + 7 dollars (since Carlos has $7 more than Diane),
Abdul has 4(X + 7) dollars (since Abdul has 4 times what Carlos has).

The total amount of money they have is $89, so we can express this as an equation:
X + (X + 7) + 4(X + 7) = 89

Now, we simplify the equation:
X + X + 7 + 4X + 28 = 89
6X + 35 = 89
6X = 89 - 35
6X = 54
X = 54/6
X = 9

So Diane has $9. Carlos, therefore, has $9 + $7 = $16, and Abdul has $16 × 4 = $64.

The correct amounts they have in their wallets are:
Diane: $9,
Carlos: $16,
Abdul: $64.

Comparing with the given options, none of them match the correct amounts calculated, meaning there is a mistake in the question choices provided.

User Daniil Ryzhkov
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