Question

What are the zeros of (x - 2)(x + 8)(1 - √2)(x + 2)?

a. 0 and 2
b. 0, 8, -7, 2
c. 0, 2, and -8
d. 2, -8, √2, -√2

Answer 1

The zeros of the polynomial (x - 2)(x + 8)(1 - √2)(x + 2) are 2, -8, √2, and -√2.

Step-by-step explanation:

The zeros of a polynomial are the values of x for which the polynomial equals zero. For the polynomial (x - 2)(x + 8)(1 - √2)(x + 2), we set each factor equal to zero to find the zeros. The zeros are the solutions to the equations x - 2 = 0, x + 8 = 0, 1 - √2 = 0, and x + 2 = 0. Solving each equation gives us the zeros 2, -8, √2, and -2 respectively. Therefore, the correct answer is 2, -8, √2, -√2.