Final answer:
The diameter of the silver disc is 132.48 cm, determined by multiplying the diameter of a single silver atom (2.88 x 10^-8 cm) by the number of silver atoms that fit side by side across the disc (46 x 10^6).
Step-by-step explanation:
To find the diameter (in cm) of the silver disc, where 46 x 10^6 silver atoms could be aligned side by side, we first need to consider the diameter of a single silver atom. Given that the radius of a silver atom is 1.44 Å (Angstroms), the diameter of a single atom would be twice the radius, which is 2.88 Å. To convert Angstroms to centimeters, remember that 1 Å equals 10^-8 cm, thus the diameter of a silver atom is 2.88 × 10^-8 cm. To compute the total diameter for the 46 x 10^6 atoms, we multiply the diameter of one atom by the number of atoms:
2.88 × 10^-8 cm/atom × 46 x 10^6 atoms = 132.48 cm
Hence, the diameter of the silver disc is 132.48 cm.