Question

An ethylene gas torch requires 200 L of gas at four atm. What will be the pressure of the gas if ethylene is supplied by a 25.0 L tank?

A. 12 atm
B. 38.4 atm
C. 32 atm
D. 45.4 atm

Answer 1

Using Boyle's Law, the pressure of ethylene gas in a 25.0 L tank when it is initially at 200 L and four atm is calculated to be 32 atm.

Step-by-step explanation:

To find the pressure of ethylene gas in a 25.0 L tank when the requirement is 200 L of gas at four atm, we assume ideal gas behavior and use Boyle's Law, which states that the product of pressure and volume is constant for a given mass of ideal gas at constant temperature (P1V1 = P2V2). We are given P1 (four atm), V1 (200 L), and V2 (25.0 L), and we need to solve for P2.

P1 × V1 = P2 × V2

(4 atm × 200 L) = P2 × 25.0 L

P2 = (4 atm × 200 L) / 25.0 L = 32 atm

So, the pressure of ethylene gas in the 25.0 L tank would be 32 atm, which corresponds to option C.