Question

Find the equation of the line in standard form with a slope of 7/5 and passing through the point (-5, -3).

a) 7x - 5y = 40
b) 5x - 7y = 40
c) 7x - 5y = -40
d) 5x - 7y = -40

Answer 1

The equation of the line in standard form with a slope of 7/5 and passing through the point (-5, -3) is 7x - 5y = -20.

Step-by-step explanation:

To find the equation of the line in standard form with a slope of 7/5 and passing through the point (-5, -3), we can use the point-slope form of a linear equation, which is:

y - y1 = m(x - x1)

Plugging in the given values, we have:

y - (-3) = (7/5)(x - (-5))

y + 3 = (7/5)(x + 5)

Multiplying both sides by 5 to clear the fraction, we get:

5(y + 3) = 7(x + 5)

Simplifying the equation, we have:

5y + 15 = 7x + 35

Now, let's rearrange the equation to get it in standard form:

7x - 5y = -20

7x - 5y = -20.

Therefore, the equation of the line in standard form is