Final answer:
The velocity of the combined cars immediately after the collision, calculated using the conservation of momentum, is approximately 2.6 m/s, which corresponds to option a.
Step-by-step explanation:
The question involves applying the principle of conservation of momentum, which states that if no external forces act on a closed system, the total momentum of the system remains constant. In the scenario provided, a locomotive with a mass of 9000 kg moving at 4.0 m/s links up with a stationary boxcar of mass 5000 kg. To find the velocity of the combined cars immediately after the collision, we use the formula:
m1 * v1 + m2 * v2 = (m1 + m2) * vf
Plugging in the known values:
9000 kg * 4.0 m/s + 5000 kg * 0 m/s = (9000 kg + 5000 kg) * vf
This simplifies to:
36000 kg*m/s = 14000 kg * vf
Dividing both sides by 14000 kg gives us:
vf = 2.57 m/s
Therefore, immediately after the collision, the combined cars will move with a velocity of approximately 2.6 m/s, which corresponds to option a.