Final answer:
The acceleration of an object that slows to a stop from 30 m/s in 7 seconds is -4.29 m/s², which indicates a deceleration.
Step-by-step explanation:
An object that slows to a stop from a velocity of 30 m/s in 7 seconds experiences an acceleration. To calculate this, we use the formula for acceleration, which is the change in velocity divided by the time taken. Acceleration (a) can be calculated using the equation:
a = (v_f - v_i) / t
where v_f is the final velocity, v_i is the initial velocity, and t is the time taken for the change. Since the object comes to a stop, v_f is 0 m/s, and the initial velocity, v_i, is given as 30 m/s. The time t taken to stop is 7 seconds.
Using these values, we get:
a = (0 m/s - 30 m/s) / 7 s
a = -30 m/s / 7 s
a = -4.29 m/s²
Since the velocity decreases, the acceleration is negative, indicating that it is a deceleration.