Final answer:
The water level in a cylindrical tank with a 35cm diameter drops by 5cm when 11 liters are drawn off, which corresponds to Option B.
Step-by-step explanation:
The question asks how far the water level drops in a cylindrical tank after drawing off 11 liters.
We can start by calculating the volume of the cylinder that would represent an 11-liter decrease. Since 1 liter is equivalent to 1000 cubic centimeters (cm3), 11 liters would be 11000 cm3.
The volume V of a cylinder is given by the formula V = πr2h, where r is the radius of the base and h is the height. To find the change in height (water drop), we rearrange the formula to solve for h: h = V / (πr2).
The internal diameter of the tank is given as 35 cm, so the radius r is half of that, 17.5 cm. Now, we can solve for the height h:
h = 11000 cm3 / (π × (17.5 cm)2)
After calculating, we find that the water level would drop by 5 cm (Option B).