Final answer:
The power required to lift a 300 N crate to a height of 5.0 meters in 6.0 seconds is calculated as 250 watts.
Step-by-step explanation:
To calculate the power required to lift the crate, we recall that power is the rate at which work is done or energy is transferred. Given that the weight of the crate is 300 N and it is lifted to a height of 5.0 meters in 6.0 seconds, the work done on the crate, which is also the gravitational potential energy gained by the crate, is equal to the product of the force and the displacement (W = F * h). In this case, W = 300 N * 5.0 m = 1500 J (joules).
Since power (P) is work (W) divided by time (t), P = W / t. Therefore, the power required to lift the crate is P = 1500 J / 6.0 s, which is 250 watts (W). So, the power required to lift the crate is 250 watts.