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With oil, the coefficient of friction for steel on steel drops to 0.18. Now how much force is needed to move the 730 N cylinder?

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Final answer:

The force needed to move the 730 N cylinder with oil is 131.4 N.

Step-by-step explanation:

The force needed to move the 730 N cylinder can be calculated using the coefficient of friction. The coefficient of friction between steel on steel with oil is 0.18. The force of friction can be calculated by multiplying the coefficient of friction by the normal force.

To find the normal force, we can use Newton's second law, which states that the normal force is equal to the weight of the object. In this case, the weight of the cylinder is 730 N.

The magnitude of the force needed to move the cylinder with oil:

Force of friction = coefficient of friction × normal force = 0.18 × 730 N = 131.4 N

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