Question

Write the equation of the line that passes through

the points (-1, 2) and (6, 3) in slope-intercept form.
Step 1: Choose (X1, y1). (-1, 2)
Step 2: x2 = 0
Y2 =

Answer 1

m = (3 - 2)/(6 - (-1)) = 1/7

2 = (1/7)(-1) + b

2 = 1/7 + b

b = 13/7

y = (1/7)x + (15/7)

Answer 2

To find the equation of the line in slope-intercept form, calculate the slope with the given points, apply the point-slope form, and rearrange to y = mx + b, resulting in the equation y = (1/7)x + 15/7.

Step-by-step explanation:

To write the equation of the line that passes through the points (-1, 2) and (6, 3) in slope-intercept form, follow these steps:

1. Calculate the slope (m) of the line using the formula m = (Y2 - Y1) / (X2 - X1), where (X1, Y1) and (X2, Y2) are the given points.
2. Using the slope obtained and one of the points, apply the point-slope form of the equation of a line which is y - Y1 = m(x - X1).
3. Rearrange the equation to the slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

Step 1: First, calculate the slope of the line.

m = (3 - 2) / (6 - (-1)) = 1 / 7

Step 2: Next, use the point-slope form with point (-1, 2).

y - 2 = (1/7)(x - (-1))

Step 3: Finally, simplify to get the slope-intercept form.

y = (1/7)x + 2 + (1/7)

y = (1/7)x + 15/7