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What is the x and y components of a vector moving at 33 m/s at 34 degrees NW?

User Justin Ko
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Final answer:

To find the components of a vector moving at 33 m/s at 34 degrees NW, we calculate Ax = 33 m/s * sin(34°) for the x-component (westward) and Ay = 33 m/s * cos(34°) for the y-component (northward).

Step-by-step explanation:

The question is about finding the x and y components of a vector that is moving at 33 m/s at 34 degrees NW (northwest). To do this, we can use trigonometry to resolve the vector into its components along the x-axis (west-east direction) and y-axis (north-south direction). Since northwest implies that the angle is measured from the north end towards the west, we need to calculate the components considering the angle of 34 degrees to the vertical (y-axis).

The component along the x-axis (west direction) is given by: Ax = 33 m/s * sin(34°). The component along the y-axis (north direction) is given by: Ay = 33 m/s * cos(34°). Note that we use sine for the x-component because the angle given is from the north axis. In this scenario, negative values for Ax would indicate westward direction and positive values for Ay would indicate northward direction.

User Mekswoll
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