Final answer:
To calculate the acceleration required for a plane to take off, use the formula a = (v^2 - u^2) / (2s), where a is acceleration, v is final velocity, u is initial velocity, and s is distance. Plug in the given values of v = 95m/s and s = 350m and assume u = 0 (since the plane starts from rest) to find the acceleration required is 136.07 m/s^2.
Step-by-step explanation:
To determine the acceleration required for a plane to take off, we can use the formula for constant acceleration, a = (v^2 - u^2) / (2s), where a is acceleration, v is final velocity, u is initial velocity, and s is distance. In this case, we know the final velocity (v) is 95m/s and the distance (s) is 350m. As the initial velocity (u) is not given, we can assume it to be 0 since the plane starts from rest. Substituting the values into the formula, we can calculate the acceleration:
a = (95^2 - 0^2) / (2 * 350) = 95^2 / 700
Therefore, the acceleration required for the plane to take off is 136.07 m/s^2.