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There (blank) grams of Cl2 in 67.2•10²¹ molecules of Cl2?

User Tbogatchev
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1 Answer

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Final answer:

There are approximately 7.91 grams of Cl2 in 67.2×10^21 molecules of Cl2, calculated using the conversion between molecules, moles, and grams.

Step-by-step explanation:

To determine how many grams of Cl2 there are in 67.2×1021 molecules of Cl2, we can use the provided conversion factors. Let's start with the number of Cl2 molecules we have and convert it to moles using Avogadro's number (6.022 × 1023 molecules per mole), and then convert moles to grams using the molar mass of Cl2 (70.90 g/mol).

First, we find the number of moles of Cl2:

67.2×1021 molecules × (1 mole / 6.022 × 1023 molecules) = 0.1116 moles of Cl2

Next, we convert the moles of Cl2 to grams:

0.1116 moles × (70.90 g / 1 mole) = 7.91 grams of Cl2

Therefore, there are approximately 7.91 grams of Cl2 in 67.2×1021 molecules of Cl2.

User Noplay
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